This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.Lecture 3 Homogeneous Spaces from the Group SL2(ℝ)
Now we adopt the previous theoretical constructions for the particular
case of the group SL2(ℝ). It is common to present SL2(ℝ) solely as
the transformation group of the Lobachevsky half-plane. We take a
wider viewpoint considering SL2(ℝ) as an abstract group and wish to
classify all its realizations as a transformation group of certain
sets. More specifically, we describe all homogeneous spaces SL2(ℝ)/H,
where H is a closed continuous subgroup of SL2(ℝ), see
Section 2.2.2. To begin with, we start from the
two-dimensional subgroup.
3.1 The Affine Group and the Real Line
The affine group of the real
line, also known as the ax+b group
, can be identified with either subgroup of
lower- or upper-triangular matrices of the form:
F= | ⎧
⎪
⎪
⎨
⎪
⎪
⎩ | | | , a>0 | ⎫
⎪
⎪
⎬
⎪
⎪
⎭ | ,
F′= | ⎧
⎪
⎪
⎨
⎪
⎪
⎩ | | | , a>0 | ⎫
⎪
⎪
⎬
⎪
⎪
⎭ | .
|
These subgroups are obviously conjugates of each other and we can
consider only the subgroup F here. We are following the construction from
Section 2.2.2 and using its notations.
Firstly, we address the simpler case of the subgroup F′ of all lower triangular
matrices in SL2(ℝ), which admits both positive and negative entries
on the main diagonal.
The corresponding homogeneous space X=SL2(ℝ)/F′ is
one-dimensional and can be parametrised by real
numbers.
We define the natural projection p as:
since there is the following decomposition:
1
The decomposition shows that each coset in SL2(ℝ)/F′ either
- contains exactly one upper-triangular matrix of the form
() and, thus, can be parametrised by the real number u; or
- is the coset of matrices
() which represents ∞.
Then, we define the smooth map s to be a right inverse of p:
The corresponding map r(g)=s(p(g))−1g is calculated to be:
Consequently, the decomposition g=s(p(g))r(g) is given by (a).
Therefore the action of SL2(ℝ)
on SL2(ℝ)/F′
is the Möbius (linear-fractional) transformations of the
projective real line $ℝ^_$=ℝ∪{∞}:
g:u↦ p(g*s(u)) = | | , where
g= | | .
(3) |
Exercise 1
-
Check that the derived actions, see Exercise 30,
associated with the one-parameter subgroups a(t), b(t) and
z(t) from Exercise 24, are, respectively:
- Verify that the above operators satisfy the commutator
relations for the Lie algebra sl2, cf. (13):
[ZF,AF]=2BF, [ZF,BF]=−2AF, [AF,BF]= − | | ZF.
(4) |
In Section 4.4, we will see the relevance of this action to projective spaces.
4
Exercise 1(a)
Formula (3) uses division
by cu+
d, how it shall be understood (or modified) if cu+
d=0
?
Hint:
A similar issue is addressed in Sec. 8.1 and can
be consistently resolved through the projective
coordinates. Another common approach is to extend arithmetic of
real numbers to the projective real line $ℝ^_$ by the
following rules involving infinity:
| | =∞,
| | =0,
| | =1,
where a≠ 0.
(a) |
As a consequence we also note that a·∞+b=a·∞
for a≠ 0. But we do not define (and, actually, will not need) values of 0/0, 0· ∞ or ∞−∞, etc.
Check, that formulae (a) together with
ordinary arithmetic define in (3) a bijection
$ℝ^_$→ $ℝ^_$
for g∈SL2(ℝ).
⋄
To describe the homogeneous space SL2(ℝ)/F and SL2(ℝ)-action on it, we rewrite the
identity (a) for d≠ 0 as:
| | =
| |
| |
| ⎛
⎜
⎜
⎜
⎜
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎟
⎟
⎟
⎟
⎠ |
| ,
(b) |
where χ is the Heaviside function (10). The
last matrix in the right-hand side of (b)
belongs to F and is uniquely defined by this identity. Thus,
cosets representing matrices with d≠ 0 are parametrised by
ℝ×{−1,+1}. The respective realisations of maps
from Section 2.2.2 are:
|
p: | SL2(ℝ)→ ℝ×{−1,+1}: | | (c) |
s: | ℝ×{−1,+1}→ SL2(ℝ): | | (d) |
r: | SL2(ℝ)→ F: |
| | ↦
| ⎛
⎜
⎜
⎜
⎜
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎟
⎟
⎟
⎟
⎠ |
| .
|
| (e) |
|
Exercise 1(b)
Extend the above
maps (c)–(e) for the
matrices with d=0
.
Hint:
Note, that all matrices
()∈SL2(ℝ) belong to two different cosets in SL2(ℝ)/F
depending from the value of χ(b). These cosets can be denoted
by (∞,+1) and (∞,−1).
⋄
Thus, the homogeneous space SL2(ℝ)/F can be identified with the
double cover of the projective real line. SL2(ℝ)-action on SL2(ℝ)/F
in terms of the above
maps (c)–(e) is:
g:(u,σ)↦ p(g*s(u,σ )) = | ⎛
⎜
⎜
⎝ | | ,
χ(cu+d)σ | ⎞
⎟
⎟
⎠ | , where
g= | | .
(f) |
Exercise 1(c)
Extend the arithmetic rules (a) and the
Heaviside function in (f) for the
exceptional cases of either u=∞
or cu+
d=0
to produce a bijection SL2(ℝ)/
F→
SL2(ℝ)/
F.
Here is some properties of the Möbius transformations of the real line:
Exercise 1(d)
-
For a non-constant Möbius transformation, there may exist only
two, one or none fixed point(s) on the real line.
-
Let x1, x2, x3 be arbitrary pairwise distinct points
of $ℝ^_$ with x2 being between x1 and
x3. Then there is the unique element in SL2(ℝ) such that the associated
Möbius transformation maps 0, 1, ∞ to x1,
x2, x3 respectively. Therefore, SL2(ℝ) acts simply
transitively on ordered triples of pair-wise distinct elements of
$ℝ^_$.
Hint:
Check that the matrix () provides the required map and normalize its determinant.
⋄
3.2 One-dimensional Subgroups of SL2(ℝ)
Any element X of the Lie algebra sl2 defines a
one-parameter continuous subgroup gX(t)=etX, t∈ℝ of
SL2(ℝ). Two such subgroups gX(t) and gY(t) with X=aY
for a non-zero a∈ ℝ coincide as sets and we can easily
re-parameterise them: gY(t)=gX(at). Therefore we will not
distinguish such subgroups in the following.
We already listed four one-parameter continuous subgroups in
Exercise 3 and can provide further examples,
e.g. the subgroup of lower-triangular matrices. However, there are only
three different types of subgroups under the matrix similarity
A↦ MAM−1.
Proposition 2
Any continuous one-parameter subgroup of SL2(ℝ)
is conjugate to one of
the following subgroups:
Proof.
Any one-parameter subgroup is obtained through the exponential map, see Section 2.3,
of an element X of the Lie algebra sl2 of
SL2(ℝ). Such an X is a 2× 2 matrix with zero trace.
The behaviour of the Taylor expansion (4) depends
on the properties of the powers Xn. This can be classified by a
straightforward calculation:
Lemma 3
The square X2 of a traceless matrix X=
(
)
is the identity matrix times a2+
bc=−det
X.
The factor can be negative, zero or positive, which corresponds to
the three different types of the Taylor
expansion (4) of etX.
It is a simple exercise in characteristic polynomials to see that, through the
matrix similarity, we can obtain from X a generator
- of the subgroup K if (−detX) <0,
- of the subgroup N if (−detX) =0,
- of the subgroup A if (−detX) >0.
The determinant is invariant under the similarity. Thus, these
cases are distinct.
Exercise 4
Find matrix conjugations of the following two subgroups to A and
N respectively:
Exercise 4(a)
-
Determine which g∈SL2(ℝ) belongs to a one-partialrightarrowmeter
subgroup, that is find the range of the exponential map X ↦
eX, where X∈ sl2 and eX∈SL2(ℝ).
Hint:
The image excludes matrices with real, negative eigenvalues,
other than −I [125]*Ex. 3.22.
⋄
- Show that g=eX∈SL2(ℝ) belongs to a subgroup
conjugated to A, N or K if and only if | tr(g) | is
bigger, equal or less than 2 respectively.
Hint:
Use the invariance of trace under matrix conjugation and the
values of trace for matrices in A, N and K.
⋄
-
Let a Möbius transformation of the real line has two, one or none
fixed points as described in
Exercise 1, then it is generated by a
matrix which is conjugated to an element of the subgroups A,
N and K respectively. Why we do not mention either the
matrix belongs to the image of exponential map in this part?
We will often use subgroups and N′ as representatives
of the corresponding equivalence classes under matrix conjugation.
An interesting property of the subgroups A, N and K is
their appearance in the
Iwasawa decomposition [240]*§ III.1 of SL2(ℝ)=ANK
in the following sense. Any element of SL2(ℝ) can be represented as
the product:
Exercise 5
Check that the values of parameters in the above decomposition are as follows:
α=(c2+d2)−1/2,
ν=ac+bd,
φ = arctan | | .
|
Consequently, cosφ=
d/√
c2+d2 and
sinφ=−
c/√
c2+d2.
The Iwasawa decomposition shows once more that SL2(ℝ) is a
three-dimensional manifold. A similar decomposition G=ANK is
possible for any semisimple Lie group G, where K is the
maximal compact group, N is nilpotent and A normalises N.
Although the Iwasawa decomposition will be used here on several
occasions, it does not play a crucial role in the present consideration.
Instead, Proposition 2 will be the cornerstone of our
construction.
3.3 Two-dimensional Homogeneous Spaces
Here, we calculate the action of SL2(ℝ) (3) (see
Section 2.2.2) on X=SL2(ℝ)/H for all three possible
one-dimensional subgroups H=, N′ or K. Counting
dimensions (3−1=2) suggests that the corresponding homogeneous
spaces are two-dimensional manifolds. In fact, we identify X in
each case with a subset of ℝ2 as follows.
First, for every equivalence class of SL2(ℝ)/H we chose a
representative, which is an upper-triangular matrix.
Exercise 6
Show that
-
For any matrix g∈SL2(ℝ) and for
each value σ=−1, 0, 1 there is a factorisation
g=gu
() for some upper-triangular 2× 2 matrix gu.
Hint:
See (9), (12) and (15).
⋄
- There is at most one upper-triangular matrix in every
equivalence class SL2(ℝ)/H, where H=, N′ or K,
where, in the last case, uniqueness is up to the constant factor ±
1. For the subgroup , there may be not such upper triangular matrix.
Hint:
The identity matrix is the only upper-triangular matrix in these
three subgroups, where, again, the uniqueness for the subgroup K
is understood up to the scalar factor ±1.
⋄
The existence of such a triangular matrix will be demonstrated in each
case separately. Now, we define the projection p:SL2(ℝ)→ X,
assigning p(g)=(a1b1,a12), where (
)
is the upper-triangular matrix1
representing the equivalence class of g.
We also choose [170]*p. 108 the map
s: X→ G in the form:
s: (u,v) ↦
| |
| | , (u,v)∈ℝ2, v>0.
(8) |
This formula will be used for all three possible subgroups H.
3.3.1 From the Subgroup K
The homogeneous space SL2(ℝ)/K is the most traditional case in
representation theory. The maps p and s defined above produce
the following decomposition g=s(p(g))r(g):
Then, the SL2(ℝ)-action defined by the formula g·
x=p(g*s(x)) (3) takes the form:
| | : (u,v)↦
| ⎛
⎜
⎜
⎝ | (au+b)(c u+d) +cav2 |
|
( c u+d)2 +(cv)2 |
| , | | ⎞
⎟
⎟
⎠ | .
(10) |
Exercise 7
Use CAS to check the above formula, as
well as analogous formulae (13)
and (1) below. See
Appendix C.3 for CAS usage.
Obviously, it preserves the upper half-plane v>0. The
expression (10) is very cumbersome and it can
be simplified by the complex imaginary unit i2=−1, which
reduces (10) to the Möbius transformation
| | : w↦ | | ,
where w=u+i v.
(11) |
We need to assign a meaning to the case cw+d=0 and this can be
done by the addition of an infinite point ∞ to the set of
complex numbers—see, for example, [26]*Definition 13.1.3
for details.
In this case, complex numbers appeared naturally.
3.3.2 From the Subgroup N′
We consider the subgroup of lower-triangular matrices
N′ (6). For this subgroup, the
representative of cosets among the upper-triangular matrices will be
different. Therefore, we receive an apparently different decomposition
g=s(p(g))r(g), cf. (9)
We postpone the treatment of the exceptional case d=0 until
Section 8.1. The SL2(ℝ)-action (3)
now takes the form:
| | : (u,v)↦
| ⎛
⎜
⎜
⎝ | | , | | ⎞
⎟
⎟
⎠ | .
(13) |
This map preserves the upper half-plane v>0 just like the case of the subgroup
K. The expression (13) is simpler
than (10), yet we can again rewrite it as
a linear-fractional transformation with the help of
the dual numbers unit ε 2=0:
| | : w↦ | | , where w=u+ε v.
(14) |
We briefly review the algebra of dual numbers in
Appendix B.1. Since they have zero divisors,
the fraction is not properly defined for all
cu+d=0. The proper treatment will be considered in
Section 8.1 since it is not as simple as in the case
of complex numbers.
3.3.3 From the Subgroup
In the last case of the subgroup , we still can obtain the decomposition
However, the new aspect is here that (15)
presents the decomposition g=s(p(g))r(g)
if and only if d2−c2>0.
Otherwise the matrix (
) is not in . If d2−c2<0 we use the decomposition
15
The modified maps p(g): G → G/H is:
The respective modification of the map s: G/H → G is:
s(u,v)= | ⎧
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎩ | |
|
(c) |
The geometrical meaning of this modification is that the homogeneous
spaces G/K
and G/N
are parametrised by points of the upper half-plane, while
G/
shall be parametrised by the union of the upper and lower
half-planes. We will further discuss this difference
Section 8.2. The exceptional situation
d=± c will be treated in Section 8.1.
The SL2(ℝ)-action (3) takes the form
| | : (u,v)↦
| ⎛
⎜
⎜
⎝ | (au+b)(c u+d) −cav2 |
|
( c u+d)2 −(cv)2 |
| , | | ⎞
⎟
⎟
⎠ | .
(1) |
Notably, this time the map does not preserve the upper
half-plane v>0: the sign of ( c u+d)2
−(cv)2 is not determined. To express this map as a Möbius
transformation, we require the double numbers
(also known as split-complex numbers) unit є 2=1:
The algebra of double numbers is briefly introduced in
Appendix B.1.
3.3.4 Unifying All Three Cases
There is an obvious similarity in the formulae obtained in each of the
above cases. To present them in a unified way, we introduce the
parameter σ which is equal to −1, 0 or 1 for the
subgroups K, N′ or , respectively. Then,
decompositions (9), (12)
and (15) are
| | =
| |
| |
| | , where d2−σ c2≠ 0.
(2) |
The respective SL2(ℝ)-actions on the homogeneous space
SL2(ℝ)/H, where H=, N′ or K,
are given by
| | : (u,v)↦
| ⎛
⎜
⎜
⎝ | (au+b)(c u+d) −σ cav2 |
|
( c u+d)2 −σ (cv)2 |
| ,
| | ⎞
⎟
⎟
⎠ | .
(3) |
Finally, this action becomes the linear-fractional (Möbius)
transformation for hypercomplex numbers in two-dimensional commutative
associative algebra (see Appendix B.1) spanned
by 1 and ι:
| | : w↦ | | , where w=u+ι v,
ι2=σ.
(4) |
Thus, a comprehensive study of SL2(ℝ)-homogeneous spaces naturally
introduces three number systems. Obviously, only
one case (complex numbers) belongs to mainstream mathematics. We
start to discover empty cells in our periodic table.
Remark 8
As we can now see, the dual and double numbers naturally appear in
relation to the group SL2(ℝ)
and, thus, their introduction
in [185, 190] was not “a purely generalistic
attempt”, cf. the remark on quaternions
of [288]*p. 4.
Remark 9
A different choice of the map s:
G/
H→
G will produce
different (but isomorphic) geometric models. In this way, we will
obtain three types of “unit disks” in
Chapter 10.
3.4 Elliptic, Parabolic and Hyperbolic Cases
As we have seen in the previous section, there is no need to be
restricted to the traditional route of complex numbers only.
The arithmetic of dual and double numbers is different from
complex numbers mainly in the following aspects:
- They have zero divisors. However, we are still able to define
their transforms by (4) in most cases. The proper
treatment of zero divisors will be done through corresponding
compactification—see Section 8.1.
- They are not algebraically closed. However, this property of
complex numbers is not used very often in analysis.
We have agreed in Section 1.1 that three
possible values −1, 0 and 1 of σ:=ι2 will be referred to here as
elliptic, parabolic and hyperbolic cases, respectively. This separation into
three cases will be referred to as the EPH classification. Unfortunately, there is a clash here with
the already established label for the Lobachevsky geometry. It is often called hyperbolic geometry because it can be realised as a Riemann
geometry on a two-sheet hyperboloid. However, within
our framework, the Lobachevsky geometry should be called elliptic and
it will have a true hyperbolic counterpart.
Notation 10
We denote the space ℝ
2 of vectors u+
v ι
by
ℝ
e, ℝ
p or ℝ
h to
highlight which number system (complex, dual or double,
respectively) is used. The notation ℝ
σ is used for a generic
case. The use of E, P, H or e, p, h (for example, in labelling the
different sections of an exercise) corresponds to the elliptic,
parabolic, hyperbolic cases.
Remark 11
In introducing the parabolic objects on a common ground with elliptic
and hyperbolic ones, we should warn against some common prejudices
suggested by the diagram (2):
-
The parabolic case is unimportant (has
“zero measure”) in comparison to the elliptic and hyperbolic cases.
As we shall see (e.g. Remark 8
and 2), the parabolic case presents some richer
geometrical features.
- The parabolic case is a limiting situation
or an intermediate position between the elliptic and hyperbolic
cases. All properties of the former can be guessed or obtained as a
limit or an average from the latter two. In particular, this point of
view is implicitly supposed in [241].
Although there are some confirmations of this (e.g.
Fig. 10.3(E)–(H)), we shall see (e.g.
Remark 21) that some properties of the
parabolic case cannot be guessed in a straightforward manner from a
combination of elliptic and hyperbolic cases.
- All three EPH cases are even less disjoint than is usually
thought. For example, there are meaningful notions of the centre of
a parabola (3) or the focus of
a circle (2).
- A (co-)invariant geometry is believed to be “coordinate-free”,
which sometimes is pushed to an absolute mantra. However, our
study within the Erlangen programme framework reveals two useful notions
(Definition 3 and (2)), mentioned
above, which are defined by coordinate expressions and look very
“non-invariant” at first glance.
3.5 Orbits of the Subgroup Actions
We start our investigation of the Möbius
transformations (4)
on the hypercomplex numbers w=u+ι v from a description of
orbits produced by the subgroups A, N and K. Due to the
Iwasawa decomposition (7), any Möbius
transformation can be represented as a superposition of these three
actions.
The actions of subgroups A and N for any kind of hypercomplex
numbers on the plane are the same as on the real line: A dilates and N shifts—see Fig. 1.1 for
illustrations. Thin traversal lines in Fig. 1.1 join
points of orbits obtained from the vertical axis by the same values of
t and grey arrows represent “local velocities”—vector fields
of derived representations.
Exercise 12
Check that:
-
The matrix ()=exp()
from A makes a dilation by e−2t, i.e. z↦
e−2t z. The respective derived action, see
Example 30, is twice the Euler operator
u∂u+v∂v.
- The matrix ()=exp()
from N shifts points horizontally by t, i.e. z↦
z+t=(u+t)+ι v. The respective derived action is ∂u.
-
The subgroup of SL2(ℝ) generated by A and N is isomorphic
to the ax+b group, which acts transitively on the upper half-plane.
Hint:
Note that the matrix
(
)=
(
)
(
)
maps ι to aι +b and use
Exercise 2.
⋄
By contrast, the action of the third matrix from the subgroup K
sharply depends on σ=ι2, as illustrated by
Fig. 1.2. In elliptic, parabolic and hyperbolic
cases, K-orbits are circles, parabolas and
(equilateral) hyperbolas, respectively. The meaning of traversal lines
and vector fields is the same as on the previous figure.
Exercise 13
The following properties characterise K-orbits:
-
The derived action of the subgroup K is given by:
Kσd(u,v)=(1+u2+σ v2)∂u+2uv∂v,
σ=ι2.
(5) |
Hint:
Use the explicit formula for Möbius transformation of the
components (3). An alternative with
CAS is provided as well, see
Appendix C.3 for usage.
⋄
-
A K-orbit in ℝσ passing the point
(0,s) has the following equation:
Hint:
Note that the equation (6) defines contour lines of the function F(u,v)=(u2−σ
v2+1)/v, that is, solve the equations
F(u,v)=const. Then, apply the
operator (5) to obtain KσdF=0.
⋄
-
The curvature of a K-orbit at point (0,s) is equal to
- The transverse line obtained from the vertical axis has the
equations:
(u2−σ v2)+2cot(2φ) u−1=0,
for
g= | | ∈ K.
(8) |
Hint:
A direct calculation for a point (0,s) in the
formula (3) is possible but demanding.
A computer symbolic calculation is provided as well.
⋄
Much more efficient proofs will be given later (see
Exercise 2), when suitable tools will be at
our disposal. It will also explain why K-orbits, which are circles,
parabolas and hyperbolas, are defined by the same
equation (6). Meanwhile, these formulae allow us to
produce geometric characterisation of K-orbits in terms of
classical notions of conic sections, cf.
Appendix B.2.
Exercise 14
Check the following properties of K-orbits (6):
-
For the elliptic case, the orbits of
K are circles. A circle with centre at
(0, (s+s−1)/2) passing through two points (0,s)
and (0,s−1).
-
For the parabolic case, the orbits of K are parabolas with the
vertical axis V. A parabola passing through (0,s) has
horizontal directrix passing through (0, s−1/(4s))
and focus at (0,s+1/(4s)).
- For the hyperbolic case, the orbits of
K are hyperbolas with asymptotes parallel to lines u=± v. A
hyperbola passing the point (0,s) has the second branch
passing (0,−s−1) and asymptotes crossing at
the point (0,(s−s−1)/2). Foci of this hyperbola are:
f1,2= | ⎛
⎜
⎜
⎝ | 0, | | ⎛
⎜
⎝ | (1± | √ | | )s−(1∓ | √ | | )s−1 | ⎞
⎟
⎠ | ⎞
⎟
⎟
⎠ | .
|
The amount of similarities between orbits in the three EPH cases suggests
that they should be unified one way or another. We start such attempts
in the next section.
3.6 Unifying EPH Cases: The First Attempt
It is well known that any K-orbit above is a conic section
and an interesting observation is that
corresponding K-orbits are, in fact, sections of the same
two-sided right-angle cone. More precisely, we define the family of
double-sided right-angle cones to be parameterized by s>0:
x2+(y− | | (s+s−1))2−(z− | | (s−s−1))2=0.
(9) |
Therefore, vertices of cones belong to the hyperbola {x=0,
y2−z2=1}—see Fig. 1.3.
Exercise 15 Derive equations for the K-orbits described in
Exercise 14 by calculation of intersection of a
cone (9) with the following planes:
-
Elliptic K-orbits are sections of
cones (9) by the plane z=0 (EE′ on
Fig. 1.3).
- Parabolic K-orbits are sections of (9) by
the plane y=± z (PP′ on Fig. 1.3).
- Hyperbolic K-orbits are sections of (9)
by the plane y=0 (HH′ on Fig. 1.3);
Moreover, each straight line generating the cone, see
Fig. 1.3(b), is crossing corresponding EPH
K-orbits at points with the same value of parameter φ
from (7). In other words, all three types of
orbits are generated by the rotations of this generator along the
cone.
Exercise 16
Verify that the rotation of a cone’s generator corresponds to the
Möbius transformations in three planes.Hint:
I do not know a smart way to check this, so a CAS solution is provided.
⋄
From the above algebraic and geometric descriptions of the orbits we
can make several observations.
Remark 17
-
The values of all three vector fields dKe, dKp and dKh
coincide on the “real” U-axis (v=0), i.e. they are three
different extensions into the domain of the same boundary
condition. Another origin of this: the axis U is the
intersection of planes EE′, PP′ and HH′ on
Fig. 1.3.
- The hyperbola passing through the point
(0,1) has the shortest focal length √2 among all
other hyperbolic orbits since it is the section of the cone
x2+(y−1)2+z2=0 closest from the family to the plane
HH′.
- Two hyperbolas passing through (0,v) and (0,v−1)
have the same focal length since they are sections of two cones
with the same distance from HH′. Moreover, two such hyperbolas
in the lower and upper half-planes passing the points
(0,v) and (0,−v−1) are sections of the same
double-sided cone. They are related to each other as explained in
Remark 4.
We make a generalisation to all EPH cases of the following notion,
which is well known for circles [71]*§ 2.3 and
parabolas [339]*§ 10:
Definition 18
A power
p of a point (
u,
v)
with respect to a
conic section given by the equation
x2−σ
y2−2
lx−2
ny+
c=0
is defined by the identity
p=u2−σ v2−2lu−2nv+c.
(10) |
Exercise 19
Check the following properties:
-
A conic section is the collection of points having zero power with
respect to the section.
-
The collection of points having the same power with respect to
two given conic sections of the above type is either empty or the
straight line. This line is called radical axis of the two sections.
-
All K-orbits are coaxial [71]*§ 2.3
with the real line being their joint radical axis, that is, for a given point on
the real line, its power with respect to any K-orbit
is the same.
-
All transverse lines (8) are coaxial, with the
vertical line u=0 being the respective radial axis.
In the case of circles the power of a point is known as Steiner power.
3.7 Isotropy Subgroups
In Section 2.2 we described the two-sided
connection between homogeneous spaces and subgroups.
Section 3.3 uses it in one direction: from
subgroups to homogeneous spaces. The following exercise does it in the
opposite way: from the group action on a homogeneous space to the
corresponding subgroup, which fixes the certain point.
Figure 3.1: Actions of isotropy subgroups
K, N′ and , which
fix point ι in three EPH cases. |
Exercise 20
Let SL2(ℝ)
act by Möbius transformations (4)
on the three number systems. Show that the isotropy subgroups
of the point ι
are:
-
The subgroup K in the elliptic case. Thus, the
elliptic upper half-plane is a model for the homogeneous space
SL2(ℝ)/K.
-
The subgroup N′ (6) of matrices
in the parabolic case. It also fixes any point ε v on the
vertical axis, which is the set of zero divisors in dual numbers. The subgroup N′ is
conjugate to subgroup N, thus the parabolic upper half-plane is
a model for the homogeneous space SL2(ℝ)/N.
-
The subgroup (5) of matrices
in the hyperbolic case. These transformations also fix the light
cone centred at є, that is, consisting of
є+zero divisors. The subgroup is conjugate to
the subgroup A, thus two copies of the upper half-plane (see
Section 8.2) are a model for SL2(ℝ)/A.
Figure 3.1 shows actions of the above isotropic
subgroups on the respective numbers, we call them rotations around ι. Note, that in parabolic and
hyperbolic cases they fix larger sets connected with zero divisors.
It is inspiring to compare the action of subgroups K, N′ and
on three number systems, this is presented on
Fig. 3.2. Some features are preserved if
we move from top to bottom along the same column, that is, keep the
subgroup and change the metric of the space. We also note the same
system of a gradual transition if we compare pictures from left to
right along a particular row. Note, that Fig. 3.1
extracts diagonal images from Fig. 3.2,
this puts three images from Fig. 3.1 into a context,
which is not obvious from Fig. 3.2. Even greater similarity in the
respective analytic expressions is presented by the next exercise.
Exercise 21
Using the parameter τ=−1
, 0
, 1
for the subgroups
K, N′
and respectively, check the following
properties of the actions of the subgroups K, N′
and
:
-
Vector fields of the respective actions are
where σ=ι2 represent the metric of the space .
-
Orbits of the isotropy subgroups , N′ and K satisfy the equation
(u2−σ v2)−2nv−τ=0,
where n∈ℝ.
(13) |
Hint:
See method used in Exercise 2. An alternative
derivation will be available in Exercise 24.
⋄
-
The isotropy subgroups of ι in all EPH cases are
uniformly expressed by matrices of the form
13
- The isotropy subgroup of a point u+ι v consists of
matrices
| ⎛
⎜
⎜
⎜
⎜
⎜
⎝ | | ⎞
⎟
⎟
⎟
⎟
⎟
⎠ |
| ∈SL2(ℝ)
|
and describe admissible values of the parameter c.Hint:
Use the previous item and the transitive action of the
ax+b from Exercise 3.
⋄
- The transverse lines on Fig. 3.2
in all nine cases are, cf. (13):
(u2−σ v2)−lu+τ=0, where l∈ℝ.
(1) |
Definition 22
In the hyperbolic case, we extend the subgroup to a
subgroup A″
by the element
(
)
.
This additional elements flips the upper and lower half-planes of double
numbers—see Section 8.2. Therefore, the
subgroup A″h fixes the set {ι,−ι}.
Lemma 23
Möbius action of SL2(ℝ)
in each EPH case is generated by
action of the corresponding isotropy subgroup (A″
h in the hyperbolic case) and
actions of the ax+
b group, e.g. subgroups A and N.
Proof.
The ax+b group acts transitively on the upper or lower
half-planes. Thus,
for any g∈SL2(ℝ), there is an h in the ax+b group such that
h−1g either fixes ι or sends it to −ι. Thus,
h−1g is in the corresponding isotropy subgroup.
3.7.1 Trigonometric Functions
The actions of isotropy subgroups can be viewed as “rotations around
ι”. In the Euclidean geometry rotations are transformations
preserving angles. Thus, we can use isotropy subgroups to define
angles in all EPH geometries as certain invariants of Möbius transformations.
Definition 24
The σ
-tangent (denoted tan
σ) between two vectors
P=(
u,
v)
and P′=(
u′,
v′)
in ℝ
σ2 is defined by:
Then, the respective σ
-cosine and σ
-sine functions are
connected to σ
-tangent by:
| cosσ2(P,P′) | | | | | | | | | | |
| = | (u u′−σ v v′)2 |
|
(u u′−σ v v′)2 −σ(u v′− v
u′)2 |
|
= | (u u′−σ v v′)2 |
|
(u2−σ v2)(u′2−σ v′2) |
|
,
|
| | | | | | | | | (3) |
sinσ2(P,P′) | = | tanσ2(P,P′) |
|
1−σ
tanσ2(P,P′) |
|
|
| | | | | | | | | |
| = | (u v′− v u′)2 |
|
(u u′−σ v v′)2 −σ(u v′− v u′)2 |
|
= | (u v′− v u′)2 |
|
(u2−σ v2)(u′2−σ v′2) |
| .
|
| | | | | | | | | (4) |
|
As a consequence we have the following EPH form of the Pythagoras
identity, cf. the identity at (a):
cosσ2(P,P′)−σ sinσ2(P,P′)=1.
(5) |
Exercise 25
Let P and P′
be two vectors tangent to
ℝ
σ2 at ι
. Denote by P′
and
P′′
images of P and P′
under the action of the
matrix (
)
from the corresponding isotropy subgroup,
see (a). Then:
-
The angle between a vector and its image is independent from
the vector:
-
The angle between vectors is preserved by the transformation:
tanσ(P,P′)=tanσ(P′,P′′). Since cosine and
sine are functions of the tangent they are preserved as well
Exercise 26
Show that the angle between any two tangent vectors at any point of
ℝ
σ2 is preserved by an arbitrary Möbius
transformation from SL2(ℝ)
.
Hint:
Use a combination of Lem. 23 and
Exercise 2.
⋄
We continue to use the standard notation tan and tanh for
the respective elliptic tane and hyperbolic tanh
functions, similarly for sines and cosines.
Last modified: October 28, 2024.